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#!/usr/bin/env python3
# $Id$
# Copyright (C) 2008 Igor Belyi <[email protected]>
# Copyright (C) 2002 John Goerzen <[email protected]>
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
"""
This program will try to encrypt a simple message to each key on your keyring.
If your keyring has any invalid keys on it, those keys will be removed
and it will re-try the encryption."""
from pyme import core
from pyme.core import Data, Context
from pyme.constants import validity
core.check_version(None)
plain = Data('This is my message.')
c = Context()
c.set_armor(1)
def sendto(keylist):
cipher = Data()
c.op_encrypt(keylist, 1, plain, cipher)
cipher.seek(0,0)
return cipher.read()
names = []
for key in c.op_keylist_all(None, 0):
print(" *** Found key for %s" % key.uids[0].uid)
valid = 0
for subkey in key.subkeys:
keyid = subkey.keyid
if keyid == None:
break
can_encrypt = subkey.can_encrypt
valid += can_encrypt
print(" Subkey %s: encryption %s" % \
(keyid, can_encrypt and "enabled" or "disabled"))
if valid:
names.append(key)
else:
print(" This key cannot be used for encryption; skipping.")
passno = 0
print("Encrypting to %d recipients" % len(names))
print(sendto(names))
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