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doc: python bindings howto

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* Promoted final encryption example so that it will appear as heading
  6.1.3 when exported to HTML or PDF.
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Ben McGinnes 2018-03-16 01:34:22 +11:00
parent 3d0c7a2202
commit 94a95ac123
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lang/python/docs/GPGMEpythonHOWTOen.org
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@ -608,71 +608,71 @@
This will attempt to encrypt to all the keys searched for, then
remove invalid recipients if it fails and try again.
**** Encrypting to one key using the second method
:PROPERTIES:
:CUSTOM_ID: howto-basic-encryption-monogamous
:END:
*** Encrypting to one key using the second method
:PROPERTIES:
:CUSTOM_ID: howto-basic-encryption-monogamous
:END:
This example re-creates the first encryption example except it
uses the same =encrypt= method used in the subsequent examples
instead of the =op_encrypt= method. This means that, unlike the
=op_encrypt= method, it /must/ use byte literal input data.
This example re-creates the first encryption example except it
uses the same =encrypt= method used in the subsequent examples
instead of the =op_encrypt= method. This means that, unlike the
=op_encrypt= method, it /must/ use byte literal input data.
#+begin_src python
import gpg
#+begin_src python
import gpg
rkey = "0x12345678DEADBEEF"
text = b"""Some text to test with.
rkey = "0x12345678DEADBEEF"
text = b"""Some text to test with.
Since the text in this case must be bytes, it is most likely that
the input form will be a separate file which is opened with "rb"
as this is the simplest method of obtaining the correct data
format.
"""
Since the text in this case must be bytes, it is most likely that
the input form will be a separate file which is opened with "rb"
as this is the simplest method of obtaining the correct data
format.
"""
c = gpg.Context(armor=True)
rpattern = list(c.keylist(pattern=rkey, secret=False))
logrus = []
c = gpg.Context(armor=True)
rpattern = list(c.keylist(pattern=rkey, secret=False))
logrus = []
for i in range(len(rpattern)):
if rpattern[i].can_encrypt == 1:
logrus.append(rpattern[i])
for i in range(len(rpattern)):
if rpattern[i].can_encrypt == 1:
logrus.append(rpattern[i])
cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
afile = open("secret_plans.txt.asc", "wb")
afile.write(cipher[0])
afile.close()
#+end_src
afile = open("secret_plans.txt.asc", "wb")
afile.write(cipher[0])
afile.close()
#+end_src
With one or two exceptions, this method will probably prove to be
easier to implement than the first method and thus it is the
recommended encryption method. Though it is even more likely to
be used like this:
With one or two exceptions, this method will probably prove to be
easier to implement than the first method and thus it is the
recommended encryption method. Though it is even more likely to
be used like this:
#+begin_src python
import gpg
#+begin_src python
import gpg
rkey = "0x12345678DEADBEEF"
rkey = "0x12345678DEADBEEF"
afile = open("secret_plans.txt", "rb")
text = afile.read()
afile.close()
afile = open("secret_plans.txt", "rb")
text = afile.read()
afile.close()
c = gpg.Context(armor=True)
rpattern = list(c.keylist(pattern=rkey, secret=False))
logrus = []
c = gpg.Context(armor=True)
rpattern = list(c.keylist(pattern=rkey, secret=False))
logrus = []
for i in range(len(rpattern)):
if rpattern[i].can_encrypt == 1:
logrus.append(rpattern[i])
for i in range(len(rpattern)):
if rpattern[i].can_encrypt == 1:
logrus.append(rpattern[i])
cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
afile = open("secret_plans.txt.asc", "wb")
afile.write(cipher[0])
afile.close()
#+end_src
afile = open("secret_plans.txt.asc", "wb")
afile.write(cipher[0])
afile.close()
#+end_src
** Decryption