python: Workaround for a regression in GnuPG 2.2.21
* lang/python/tests/support.py (is_gpg_version): New. * lang/python/tests/t-encrypt-sym.py: Add workaround. -- GnuPG-bug-id: 4991 Signed-off-by: Werner Koch <wk@gnupg.org>
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@ -38,6 +38,12 @@ def assert_gpg_version(version=(2, 1, 0)):
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c.engine_info.version, '.'.join(map(str, version))))
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sys.exit(77)
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def is_gpg_version(version):
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with gpg.Context() as c:
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clean_version = re.match(r'\d+\.\d+\.\d+',
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c.engine_info.version).group(0)
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return tuple(map(int, clean_version.split('.'))) == version
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def have_tofu_support(ctx, some_uid):
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keys = list(
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@ -44,8 +44,16 @@ for passphrase in ("abc", b"abc"):
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c.set_passphrase_cb(passphrase_cb, None)
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c.op_encrypt([], 0, source, cipher)
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assert passphrase_cb_called == 1, \
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"Callback called {} times".format(passphrase_cb_called)
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# gpg 2.2.21 has a bug in that for a new passphrase the callback
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# is called twice. This is fixed in 2.2.22 but a patch was also
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# distributed so that we allow both.
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if support.is_gpg_version((2,2,21)):
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print("Enabling GnuPG 2.2.21 bug 4991 test workaround.")
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assert passphrase_cb_called == 1 or passphrase_cb_called == 2, \
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"Callback called {} times".format(passphrase_cb_called)
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else:
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assert passphrase_cb_called == 1, \
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"Callback called {} times".format(passphrase_cb_called)
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support.print_data(cipher)
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c = gpg.Context()
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