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Updated encrypt-to-all

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* Changed plaintext string to byte literal.
* Nested key selection in a try/except statement in case of
  UnicodeEncodeError instances.
* Tested successfully on over 9,000 keys.
This commit is contained in:
Ben McGinnes 2015-05-17 04:03:49 +10:00
parent 24c738f5bb
commit 1c87ecb86a
1 changed files with 17 additions and 14 deletions
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31
lang/py3-pyme/examples/encrypt-to-all.py
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@ -18,9 +18,9 @@
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
"""
This program will try to encrypt a simple message to each key on your keyring.
If your keyring has any invalid keys on it, those keys will be removed
and it will re-try the encryption."""
This program will try to encrypt a simple message to each key on your
keyring. If your keyring has any invalid keys on it, those keys will
be skipped and it will re-try the encryption."""
from pyme import core
from pyme.core import Data, Context
@ -28,7 +28,7 @@ from pyme.constants import validity
core.check_version(None)
plain = Data('This is my message.')
plain = Data(b'This is my message.')
c = Context()
c.set_armor(1)
@ -41,16 +41,19 @@ def sendto(keylist):
names = []
for key in c.op_keylist_all(None, 0):
print(" *** Found key for %s" % key.uids[0].uid)
valid = 0
for subkey in key.subkeys:
keyid = subkey.keyid
if keyid == None:
break
can_encrypt = subkey.can_encrypt
valid += can_encrypt
print(" Subkey %s: encryption %s" % \
(keyid, can_encrypt and "enabled" or "disabled"))
try:
print(" *** Found key for %s" % key.uids[0].uid)
valid = 0
for subkey in key.subkeys:
keyid = subkey.keyid
if keyid == None:
break
can_encrypt = subkey.can_encrypt
valid += can_encrypt
print(" Subkey %s: encryption %s" % \
(keyid, can_encrypt and "enabled" or "disabled"))
except UnicodeEncodeError as e:
print(e)
if valid:
names.append(key)