31 lines
813 B
C
31 lines
813 B
C
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#include<stdio.h>
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double max(double a,double b) //求两者中大的
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{
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return a>b?a:b;
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}
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double min(double c,double d) //求两者中小的
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{
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return c<d?c:d;
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}
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void solve()
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{
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double x1,y1,x2,y2,x3,y3,x4,y4,t;
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while(scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4)!=EOF)
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{
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if(x1>x2) t=x1,x1=x2,x2=t;// 保证x2>x1。符合图中的情况。
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if(y1>y2) t=y1,y1=y2,y2=t;//同上
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if(x3>x4) t=x3,x3=x4,x4=t;//同上
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if(y3>y4) t=y3,y3=y4,y4=t;//同上
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double l=min(x2,x4)-max(x1,x3);// 求宽
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double d=min(y2,y4)-max(y1,y3);// 求高。
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double s=l*d; //求面积。
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printf("%.2lf\n",max(x1,x3)>min(x2,x4)||max(y1,y3)>min(y2,y4)?0:s);//如果高或宽小于0解为0，即没有相交的部分，否则输出面积
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}
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}
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int main()
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{
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solve();//问题解决。
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return 0;
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}
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