doc: python bindings howto

* Promoted final encryption example so that it will appear as heading
  6.1.3 when exported to HTML or PDF.

1 files changed, 49 insertions, 49 deletions

diff --git a/lang/python/docs/GPGMEpythonHOWTOen.org b/lang/python/docs/GPGMEpythonHOWTOen.org
index 71e738ac..30e10184 100644
--- a/lang/python/docs/GPGMEpythonHOWTOen.org
+++ b/lang/python/docs/GPGMEpythonHOWTOen.org
@@ -608,71 +608,71 @@
     This will attempt to encrypt to all the keys searched for, then
     remove invalid recipients if it fails and try again.
 
-**** Encrypting to one key using the second method
-     :PROPERTIES:
-     :CUSTOM_ID: howto-basic-encryption-monogamous
-     :END:
+*** Encrypting to one key using the second method
+    :PROPERTIES:
+    :CUSTOM_ID: howto-basic-encryption-monogamous
+    :END:
 
-     This example re-creates the first encryption example except it
-     uses the same =encrypt= method used in the subsequent examples
-     instead of the =op_encrypt= method.  This means that, unlike the
-     =op_encrypt= method, it /must/ use byte literal input data.
+    This example re-creates the first encryption example except it
+    uses the same =encrypt= method used in the subsequent examples
+    instead of the =op_encrypt= method.  This means that, unlike the
+    =op_encrypt= method, it /must/ use byte literal input data.
 
-     #+begin_src python
-       import gpg
+    #+begin_src python
+      import gpg
 
-       rkey = "0x12345678DEADBEEF"
-       text = b"""Some text to test with.
+      rkey = "0x12345678DEADBEEF"
+      text = b"""Some text to test with.
 
-       Since the text in this case must be bytes, it is most likely that
-       the input form will be a separate file which is opened with "rb"
-       as this is the simplest method of obtaining the correct data
-       format.
-       """
+      Since the text in this case must be bytes, it is most likely that
+      the input form will be a separate file which is opened with "rb"
+      as this is the simplest method of obtaining the correct data
+      format.
+      """
 
-       c = gpg.Context(armor=True)
-       rpattern = list(c.keylist(pattern=rkey, secret=False))
-       logrus = []
+      c = gpg.Context(armor=True)
+      rpattern = list(c.keylist(pattern=rkey, secret=False))
+      logrus = []
 
-       for i in range(len(rpattern)):
-	   if rpattern[i].can_encrypt == 1:
-	       logrus.append(rpattern[i])
+      for i in range(len(rpattern)):
+	  if rpattern[i].can_encrypt == 1:
+	      logrus.append(rpattern[i])
 
-       cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
+      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
 
-       afile = open("secret_plans.txt.asc", "wb")
-       afile.write(cipher[0])
-       afile.close()
-     #+end_src
+      afile = open("secret_plans.txt.asc", "wb")
+      afile.write(cipher[0])
+      afile.close()
+    #+end_src
 
-     With one or two exceptions, this method will probably prove to be
-     easier to implement than the first method and thus it is the
-     recommended encryption method.  Though it is even more likely to
-     be used like this:
+    With one or two exceptions, this method will probably prove to be
+    easier to implement than the first method and thus it is the
+    recommended encryption method.  Though it is even more likely to
+    be used like this:
 
-     #+begin_src python
-       import gpg
+    #+begin_src python
+      import gpg
 
-       rkey = "0x12345678DEADBEEF"
+      rkey = "0x12345678DEADBEEF"
 
-       afile = open("secret_plans.txt", "rb")
-       text = afile.read()
-       afile.close()
+      afile = open("secret_plans.txt", "rb")
+      text = afile.read()
+      afile.close()
 
-       c = gpg.Context(armor=True)
-       rpattern = list(c.keylist(pattern=rkey, secret=False))
-       logrus = []
+      c = gpg.Context(armor=True)
+      rpattern = list(c.keylist(pattern=rkey, secret=False))
+      logrus = []
 
-       for i in range(len(rpattern)):
-	   if rpattern[i].can_encrypt == 1:
-	       logrus.append(rpattern[i])
+      for i in range(len(rpattern)):
+	  if rpattern[i].can_encrypt == 1:
+	      logrus.append(rpattern[i])
 
-       cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
+      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
 
-       afile = open("secret_plans.txt.asc", "wb")
-       afile.write(cipher[0])
-       afile.close()
-     #+end_src
+      afile = open("secret_plans.txt.asc", "wb")
+      afile.write(cipher[0])
+      afile.close()
+    #+end_src
 
 
 ** Decryption