2f12427e41
-- Signed-off-by: Daniel Kahn Gillmor <dkg@fifthhorseman.net>
65 lines
2.4 KiB
Python
Executable File
65 lines
2.4 KiB
Python
Executable File
#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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from __future__ import absolute_import, division, unicode_literals
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# Copyright (C) 2018 Ben McGinnes <ben@gnupg.org>
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#
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# This program is free software; you can redistribute it and/or modify it under
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# the terms of the GNU General Public License as published by the Free Software
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# Foundation; either version 2 of the License, or (at your option) any later
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# version.
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#
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# This program is free software; you can redistribute it and/or modify it under
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# the terms of the GNU Lesser General Public License as published by the Free
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# Software Foundation; either version 2.1 of the License, or (at your option)
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# any later version.
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#
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# This program is distributed in the hope that it will be useful, but WITHOUT
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# ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
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# FOR A PARTICULAR PURPOSE. See the GNU General Public License and the GNU
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# Lesser General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License and the GNU
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# Lesser General Public along with this program; if not, see
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# <https://www.gnu.org/licenses/>.
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import sys
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from groups import group_lists
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"""
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Uses the groups module to generate Mutt crypt-hooks from gpg.conf.
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"""
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if len(sys.argv) >= 2:
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hook_file = sys.argv[1]
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else:
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hook_file = input("Enter the filename to save the crypt-hooks in: ")
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with open(hook_file, "w") as f:
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f.write("""# Change settings based upon message recipient
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#
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# send-hook [!]<pattern> <command>
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#
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# <command> is executed when sending mail to an address matching <pattern>
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#
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# crypt-hook regexp key-id
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# The crypt-hook command provides a method by which you can
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# specify the ID of the public key to be used when encrypting
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# messages to a certain recipient. The meaning of "key ID" is to
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# be taken broadly: This can be a different e-mail address, a
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# numerical key ID, or even just an arbitrary search string. You
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# may use multiple crypt-hooks with the same regexp; multiple
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# matching crypt-hooks result in the use of multiple key-ids for a
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# recipient.
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""")
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for n in range(len(group_lists)):
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rule = group_lists[n][0].replace(".", "\\\\.")
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with open(hook_file, "a") as f:
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f.write("\n")
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f.write("# {0}\n".format(group_lists[n][0]))
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for i in range(len(group_lists[n][1])):
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f.write("crypt-hook {0} {1}\n".format(rule, group_lists[n][1][i]))
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