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| -rw-r--r-- | lang/python/docs/GPGMEpythonHOWTOen.org | 98 |
1 files changed, 49 insertions, 49 deletions
diff --git a/lang/python/docs/GPGMEpythonHOWTOen.org b/lang/python/docs/GPGMEpythonHOWTOen.org index 71e738ac..30e10184 100644 --- a/lang/python/docs/GPGMEpythonHOWTOen.org +++ b/lang/python/docs/GPGMEpythonHOWTOen.org @@ -608,71 +608,71 @@ This will attempt to encrypt to all the keys searched for, then remove invalid recipients if it fails and try again. -**** Encrypting to one key using the second method - :PROPERTIES: - :CUSTOM_ID: howto-basic-encryption-monogamous - :END: +*** Encrypting to one key using the second method + :PROPERTIES: + :CUSTOM_ID: howto-basic-encryption-monogamous + :END: - This example re-creates the first encryption example except it - uses the same =encrypt= method used in the subsequent examples - instead of the =op_encrypt= method. This means that, unlike the - =op_encrypt= method, it /must/ use byte literal input data. + This example re-creates the first encryption example except it + uses the same =encrypt= method used in the subsequent examples + instead of the =op_encrypt= method. This means that, unlike the + =op_encrypt= method, it /must/ use byte literal input data. - #+begin_src python - import gpg + #+begin_src python + import gpg - rkey = "0x12345678DEADBEEF" - text = b"""Some text to test with. + rkey = "0x12345678DEADBEEF" + text = b"""Some text to test with. - Since the text in this case must be bytes, it is most likely that - the input form will be a separate file which is opened with "rb" - as this is the simplest method of obtaining the correct data - format. - """ + Since the text in this case must be bytes, it is most likely that + the input form will be a separate file which is opened with "rb" + as this is the simplest method of obtaining the correct data + format. + """ - c = gpg.Context(armor=True) - rpattern = list(c.keylist(pattern=rkey, secret=False)) - logrus = [] + c = gpg.Context(armor=True) + rpattern = list(c.keylist(pattern=rkey, secret=False)) + logrus = [] - for i in range(len(rpattern)): - if rpattern[i].can_encrypt == 1: - logrus.append(rpattern[i]) + for i in range(len(rpattern)): + if rpattern[i].can_encrypt == 1: + logrus.append(rpattern[i]) - cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True) + cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True) - afile = open("secret_plans.txt.asc", "wb") - afile.write(cipher[0]) - afile.close() - #+end_src + afile = open("secret_plans.txt.asc", "wb") + afile.write(cipher[0]) + afile.close() + #+end_src - With one or two exceptions, this method will probably prove to be - easier to implement than the first method and thus it is the - recommended encryption method. Though it is even more likely to - be used like this: + With one or two exceptions, this method will probably prove to be + easier to implement than the first method and thus it is the + recommended encryption method. Though it is even more likely to + be used like this: - #+begin_src python - import gpg + #+begin_src python + import gpg - rkey = "0x12345678DEADBEEF" + rkey = "0x12345678DEADBEEF" - afile = open("secret_plans.txt", "rb") - text = afile.read() - afile.close() + afile = open("secret_plans.txt", "rb") + text = afile.read() + afile.close() - c = gpg.Context(armor=True) - rpattern = list(c.keylist(pattern=rkey, secret=False)) - logrus = [] + c = gpg.Context(armor=True) + rpattern = list(c.keylist(pattern=rkey, secret=False)) + logrus = [] - for i in range(len(rpattern)): - if rpattern[i].can_encrypt == 1: - logrus.append(rpattern[i]) + for i in range(len(rpattern)): + if rpattern[i].can_encrypt == 1: + logrus.append(rpattern[i]) - cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True) + cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True) - afile = open("secret_plans.txt.asc", "wb") - afile.write(cipher[0]) - afile.close() - #+end_src + afile = open("secret_plans.txt.asc", "wb") + afile.write(cipher[0]) + afile.close() + #+end_src ** Decryption |