diff --git a/lang/python/docs/GPGMEpythonHOWTOen.org b/lang/python/docs/GPGMEpythonHOWTOen.org
index a2144235..c0606dd9 100644
--- a/lang/python/docs/GPGMEpythonHOWTOen.org
+++ b/lang/python/docs/GPGMEpythonHOWTOen.org
@@ -511,6 +511,70 @@
 	     print(ex.getstring())
    #+end_src
 
+*** Encrypting to one key using the second method
+    :PROPERTIES:
+    :CUSTOM_ID: howto-basic-encryption-monogamous
+    :END:
+
+    This example re-creates the first encryption example except it
+    uses the same =encrypt= method used in the subsequent examples
+    instead of the =op_encrypt= method.  This means that, unlike the
+    =op_encrypt= method, it /must/ use byte literal input data.
+
+    #+begin_src python
+      import gpg
+
+      rkey = "0x12345678DEADBEEF"
+      text = b"""Some text to test with.
+
+      Since the text in this case must be bytes, it is most likely that
+      the input form will be a separate file which is opened with "rb"
+      as this is the simplest method of obtaining the correct data
+      format.
+      """
+
+      c = gpg.Context(armor=True)
+      rpattern = list(c.keylist(pattern=rkey, secret=False))
+      logrus = []
+
+      for i in range(len(rpattern)):
+	  if rpattern[i].can_encrypt == 1:
+	      logrus.append(rpattern[i])
+
+      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
+
+      with open("secret_plans.txt.asc", "wb") as afile:
+          afile.write(cipher[0])
+    #+end_src
+
+    With one or two exceptions, this method will probably prove to be
+    easier to implement than the first method and thus it is the
+    recommended encryption method.  Though it is even more likely to
+    be used like this:
+
+    #+begin_src python
+      import gpg
+
+      rkey = "0x12345678DEADBEEF"
+
+      afile = open("secret_plans.txt", "rb")
+      text = afile.read()
+      afile.close()
+
+      c = gpg.Context(armor=True)
+      rpattern = list(c.keylist(pattern=rkey, secret=False))
+      logrus = []
+
+      for i in range(len(rpattern)):
+	  if rpattern[i].can_encrypt == 1:
+	      logrus.append(rpattern[i])
+
+      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
+
+      with open("secret_plans.txt.asc", "wb") as afile:
+          afile.write(cipher[0])
+    #+end_src
+
 *** Encrypting to multiple keys
     :PROPERTIES:
     :CUSTOM_ID: howto-basic-encryption-multiple
@@ -610,70 +674,6 @@
     This will attempt to encrypt to all the keys searched for, then
     remove invalid recipients if it fails and try again.
 
-*** Encrypting to one key using the second method
-    :PROPERTIES:
-    :CUSTOM_ID: howto-basic-encryption-monogamous
-    :END:
-
-    This example re-creates the first encryption example except it
-    uses the same =encrypt= method used in the subsequent examples
-    instead of the =op_encrypt= method.  This means that, unlike the
-    =op_encrypt= method, it /must/ use byte literal input data.
-
-    #+begin_src python
-      import gpg
-
-      rkey = "0x12345678DEADBEEF"
-      text = b"""Some text to test with.
-
-      Since the text in this case must be bytes, it is most likely that
-      the input form will be a separate file which is opened with "rb"
-      as this is the simplest method of obtaining the correct data
-      format.
-      """
-
-      c = gpg.Context(armor=True)
-      rpattern = list(c.keylist(pattern=rkey, secret=False))
-      logrus = []
-
-      for i in range(len(rpattern)):
-	  if rpattern[i].can_encrypt == 1:
-	      logrus.append(rpattern[i])
-
-      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
-
-      with open("secret_plans.txt.asc", "wb") as afile:
-          afile.write(cipher[0])
-    #+end_src
-
-    With one or two exceptions, this method will probably prove to be
-    easier to implement than the first method and thus it is the
-    recommended encryption method.  Though it is even more likely to
-    be used like this:
-
-    #+begin_src python
-      import gpg
-
-      rkey = "0x12345678DEADBEEF"
-
-      afile = open("secret_plans.txt", "rb")
-      text = afile.read()
-      afile.close()
-
-      c = gpg.Context(armor=True)
-      rpattern = list(c.keylist(pattern=rkey, secret=False))
-      logrus = []
-
-      for i in range(len(rpattern)):
-	  if rpattern[i].can_encrypt == 1:
-	      logrus.append(rpattern[i])
-
-      cipher = c.encrypt(text, recipients=logrus, sign=False, always_trust=True)
-
-      with open("secret_plans.txt.asc", "wb") as afile:
-          afile.write(cipher[0])
-    #+end_src
-
 
 ** Decryption
    :PROPERTIES: