66 lines
2.0 KiB
Python
66 lines
2.0 KiB
Python
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#!/usr/bin/env python3
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# $Id$
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# Copyright (C) 2008 Igor Belyi <belyi@users.sourceforge.net>
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# Copyright (C) 2002 John Goerzen <jgoerzen@complete.org>
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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"""
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This program will try to encrypt a simple message to each key on your keyring.
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If your keyring has any invalid keys on it, those keys will be removed
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and it will re-try the encryption."""
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from pyme import core
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from pyme.core import Data, Context
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from pyme.constants import validity
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core.check_version(None)
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plain = Data('This is my message.')
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c = Context()
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c.set_armor(1)
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def sendto(keylist):
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cipher = Data()
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c.op_encrypt(keylist, 1, plain, cipher)
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cipher.seek(0,0)
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return cipher.read()
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names = []
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for key in c.op_keylist_all(None, 0):
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print(" *** Found key for %s" % key.uids[0].uid)
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valid = 0
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for subkey in key.subkeys:
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keyid = subkey.keyid
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if keyid == None:
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break
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can_encrypt = subkey.can_encrypt
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valid += can_encrypt
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print(" Subkey %s: encryption %s" % \
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(keyid, can_encrypt and "enabled" or "disabled"))
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if valid:
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names.append(key)
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else:
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print(" This key cannot be used for encryption; skipping.")
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passno = 0
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print("Encrypting to %d recipients" % len(names))
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print(sendto(names))
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